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(4xy)^2-(6xy+7)(3xy-8)

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Jeremiaid
So, subtraction and multiplication of polynomials, in this case, we should multiply the last two polynomials first before subtracting it from the minuend.

(4xy)² - (6xy + 7) (3xy - 8)

= (4²x²y²) - 18x²y² - 27xy - 56
= 16x²y² - 18x²y² - 27xy - 56
= -2x²y² - 27xy - 56
Elensapid
[tex](4xy)^2-(6xy+7)(3xy-8)= \\ 16x^2y^2-(18x^2y^2-48xy+21xy-56)= \\ 16x^2y^2-18x^2y^2+48xy-21xy+56= \\ \boxed{Answer:27xy-2x^2y^2+56}[/tex]

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