Baitanalynid
Answered

mark has four more 5-peso coins than 1 peso coin. if he has 22 coins in all, how much more does he have.

Sagot :

Daedalusid
Let x be the number of 5 peso coin and y be the number of one peso coin
[tex]x=y+4 \\ x+y=22 \\ (y+4)+y=22 \\ 2y=22-4 \\ 2y=18 \\ y=9 \\ x =13\\[/tex]

so Mark got (5*13 + 1*9) = (65 + 9) = 74 pesos :)

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