Jenycid
Jenycid
Math
Answered
find four consecutive multiples of 5 whose sum is 90
Sagot :
Daedalusid
Daedalusid
5x + 5(x+1) + 5(x+2) + 5(x+3) = 90
5x+5x+5+5x+10+5x+15=90
20x+30=90
20x=90-30
20x=60
x=3
the numbers are 15,20,25,30
Answer Link
Elensapid
Elensapid
[tex]5k+5k+5+5k+10+5k+15=90 \\ 20k+30=90|-30 \\ 20k=60|:20 \\ \underline{k=3} \\ \boxed{5k=15} \\ \boxed{5k+5=20} \\ \boxed{5k+10=25} \\ \boxed{5k+15=30}[/tex]
Answer Link
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