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the inverted pyramidal tank has an equilateral triangular base 3 ft on a side and an altitude of 7 ft. a.) how many gallons of water can the tank hold? b.) what will be the wetted area of the pyramid if the depth of the water is 4 ft?

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Daedalusid
a.) [tex]V = \frac{1}{3}b^{2}h = \frac{\sqrt{3}ha^{2}}{12} = \frac{\sqrt{3}*7*3^{2}}{12} = \frac{63\sqrt{3}}{12} = \frac{21\sqrt{3}}{4} [/tex]