Lesquenid
Answered

Leo has ten more 5.00 coins than 10.00 coins and has twice as much 1.00 coin than 5.00 coins. If he has a total of 42 coins, how much money does he have ?

Sagot :

Ronajosueid
Php 10 = 3 coins = php 30
Php 5 = 13 coins= php 65
Php 1 = 26 coins= php 26
3+13+26= 42 coins in all
php 30+65+26= Php 121 in all
Jeremiaid
x= no. of 10 peso coins
x + 10 = no. of 5 peso coins
2 ( x + 10 ) = no. of 1 peso coins

(x) + (x+10) + [ 2 ( x + 10 ) = total no. of coins
x + x + 10 + 2x + 20 = 42
2x + 10 + 2x + 20 = 42
4x + 10 + 20 = 42
4x + 30 = 42
4x = 42 - 30
4x = 12
4x x 1/4 = 12 x 1/4
4/4x = 12/4
x = 3

x = 3 = no. of 10 peso  coins
x + 10 = 3 + 10 = 13 = no. of 5 peso coins
2 ( x + 10 ) = 2x + 20 = 6 + 20 = 26 = no. of 1 peso coins

Check:
3 + 13 + 26 = 42, TRUE

3 x P10 = P30
13 x P5 = P65
26 x P1 = P26
       
                = P 121