Answered

what is the shortest distance from the point (3,1) to the line y = 2x + 1?

Sagot :

Daedalusid
you should get a line perpendicular to the line y=2x+1 containing the point (3,1)

[tex]m_{1} = 2 \\ m_{1}*m_{2} = -1 \\ m_{2} = \frac{-1}{2} m_{2} = \frac{y-3}{x-1} \\ \frac{-1}{2} = \frac{y-1}{x-3} \\ -x+3 = 2y-2 \\ x+2y-5=0[/tex]